BODMAS Questions for Class 6 with Answers

BODMAS simply means Brackets, Orders, Division, Multiplication, Addition and Subtraction. Many students get confused in the right order of solving question, that’s why practicing bodmas questions for class 6 is so helpful. In the CBSE Class 6 Maths Syllabus, this topic is very important because it clear the base for higher classes.

Students often face simple but tricky expressions like 25 – 5 × 2 + (10 ÷ 2). If you do not follow the steps in correct order, answer will come wrong. That is the reason NCERT Solutions provide easy examples and teachers always advice to solve from NCERT Solutions for Class 6 Maths. With constant practice of bodmas questions with answers class 6, you will improve both accuracy and speed.

In class 6 exams, you may also get CBSE Class 6 Maths MCQs where you need to apply the BODMAS rule very quickly. To help you more, there are resources like bodmas questions for class 6 with all brackets, bodmas questions for class 6 with answers pdf, and also bodmas questions with answers pdf class 6 available online.

What is BODMAS?

BODMAS is a very basic and imp rule in mathematics. It stands for Brackets, Orders, Division, Multiplication, Addition, and Subtraction. This rule tells us the correct order of operation when we solve maths expressions. If you don’t follow BODMAS, then answer may come wrong or confusing. That’s why bodmas questions for class 6 are usually given in the CBSE Class 6 Maths Syllabus and also in NCERT Solutions for Class 6 Maths.

Breaking down the BODMAS Rule

• Brackets: First we solve the values inside brackets. Brackets can be round ( ), square [ ], or curly { }. Always finish these first to avoid mistakes.
• Orders: After brackets, check for powers and roots like 2³ or Root 9. These are called orders.
• Division and Multiplication: Next step is to do division and multiplication, but always from left to right.
• Addition and Subtraction: At the last, we solve addition and subtraction, also from left to right.

For Class 6 students, learning this rule is very useful because it helps in solving bodmas questions with answers class 6, MCQs and even tricky sums with all brackets. Understanding BODMAS improves accuracy, calculation speed and makes maths more easy to handle. This also prepare the base for future topics like algebra and equations.

BODMAS Questions for Class 6 with Answers

Here are some BODMAS questions for Class 6 with solutions to help students understand how to apply the BODMAS rule effectively in different scenarios.

Question 1: Calculate the following: 7 + 3 × (8 - 5)

Answer:

1. First, solve the expression inside the brackets: 8 - 5 = 3.
2. Then, multiply the result by 3: 3 × 3 = 9.
3. Finally, add 7 to the product: 7 + 9 = 16.

Result: 16

Question 2: Simplify the expression: (15 - 9) ÷ 3 + 6

Answer:

1. Start with the brackets: 15 - 9 = 6.
2. Divide the result by 3: 6 ÷ 3 = 2.
3. Add 6 to the quotient: 2 + 6 = 8.

Result: 8

Question 3: Evaluate: 4 + 18 ÷ (9 - 3) × 2

Answer:

1. Solve the expression inside the brackets: 9 - 3 = 6.
2. Divide 18 by the result: 18 ÷ 6 = 3.
3. Multiply by 2: 3 × 2 = 6.
4. Finally, add 4 to the product: 4 + 6 = 10.

Result: 10

Question 4: Work out: (5 × 2) + 3^2

Answer:

1. Calculate the multiplication inside the brackets: 5 × 2 = 10.
2. Solve the power (order): 3^2 = 9.
3. Add the two results together: 10 + 9 = 19.

Result: 19

Question 5: Find the value of: 8 × (2 + 6) ÷ 4

Answer:

1. Start with the brackets: 2 + 6 = 8.
2. Multiply by 8: 8 × 8 = 64.
3. Divide the product by 4: 64 ÷ 4 = 16.

Result: 16

Q1. 25 + 36 ÷ 6 - 4

Answer

• Division: 36 ÷ 6 = 6
• Expression becomes: 25 + 6 - 4
• Add and subtract left to right: 25 + 6 = 31, then 31 - 4 = 27

Final Answer: 27

Q2. 50 - (12 ÷ 3) × 2

Answer

• Bracket: 12 ÷ 3 = 4
• Multiply: 4 × 2 = 8
• Subtract: 50 - 8 = 42

Final Answer: 42

Q3. 18 ÷ (6 - 3) + 5 × 2

Answer

• Bracket: 6 - 3 = 3
• Division: 18 ÷ 3 = 6
• Multiplication: 5 × 2 = 10
• Add: 6 + 10 = 16

Final Answer: 16

Q4. (45 ÷ 5) + (12 - 6) × 3

Answer

• Brackets: 45 ÷ 5 = 9 and 12 - 6 = 6
• Multiplication: 6 × 3 = 18
• Add: 9 + 18 = 27

Final Answer: 27

Q5. 60 ÷ (5 + 1) × 2

Answer

• Bracket: 5 + 1 = 6
• Division: 60 ÷ 6 = 10
• Multiplication: 10 × 2 = 20

Final Answer: 20

Q6. If x = 4, solve 20 ÷ (x + 1) + 3

Answer

• Substitute: 20 ÷ (4 + 1) + 3
• Bracket: 4 + 1 = 5
• Division: 20 ÷ 5 = 4
• Add: 4 + 3 = 7

Final Answer: 7

Q7. If y = 2, solve (10 - y) × 3 + 8

Answer

• Substitute: (10 - 2) × 3 + 8
• Bracket: 10 - 2 = 8
• Multiplication: 8 × 3 = 24
• Add: 24 + 8 = 32

Final Answer: 32

Q8. Simplify (x × 2 + 5) ÷ (x + 1) for x = 3

Answer

• Substitute: (3 × 2 + 5) ÷ (3 + 1)
• Multiply and add in numerator: 3 × 2 = 6, then 6 + 5 = 11
• Bracket in denominator: 3 + 1 = 4
• Division: 11 ÷ 4 = 2.75

Final Answer: 2.75

Q9. Solve 30 ÷ (2x) + 7 when x = 5

Answer

• Substitute: 30 ÷ (2 × 5) + 7
• Multiplication in bracket: 2 × 5 = 10
• Division: 30 ÷ 10 = 3
• Add: 3 + 7 = 10

Final Answer: 10

Q10. If x = 2 and y = 3, solve (x + y) × (x × y)

Answer

• Substitute: (2 + 3) × (2 × 3)
• Brackets: 2 + 3 = 5 and 2 × 3 = 6
• Multiplication: 5 × 6 = 30

Final Answer: 30

BODMAS Questions for Class 6 with All Brackets

Here are some BODMAS Questions for Class 6 with Solutions for all brackets including, round brackets, square brackets and curly brackets

BODMAS Questions with Round Brackets (Parentheses) for Class 6

Question 1: Evaluate: (6 + 4) × (3 - 1)

Solution:

1. First, solve the expressions inside the round brackets: 6 + 4 = 10 and 3 - 1 = 2.
2. Then, multiply the results: 10 × 2 = 20.

Answer: 20

Question 2: Simplify: 8 + (5 × (2 + 3))

Solution:

1. Start with the innermost round brackets: 2 + 3 = 5.
2. Multiply the result by 5: 5 × 5 = 25.
3. Add 8 to the product: 8 + 25 = 33.

Answer: 33

Question 3: Calculate: (9 - (4 + 5)) × 3

Solution:

1. First, solve the expression inside the inner round brackets: 4 + 5 = 9.
2. Subtract this result from 9: 9 - 9 = 0.
3. Multiply the result by 3: 0 × 3 = 0.

Answer: 0

BODMAS Questions for Class 6 with Square Brackets

Question 1: Work out: 4 × [15 - (6 + 3)]

Solution:

1. Start with the round brackets: 6 + 3 = 9.
2. Subtract this from 15 in the square brackets: 15 - 9 = 6.
3. Multiply the result by 4: 4 × 6 = 24.

Answer: 24

Question 2: Simplify: [12 ÷ (6 - 2)] + 3

Solution:

1. Solve inside the round brackets: 6 - 2 = 4.
2. Divide 12 by the result inside the square brackets: 12 ÷ 4 = 3.
3. Add 3 to the quotient: 3 + 3 = 6.

Answer: 6

Question 3: Evaluate: [18 ÷ (9 - (6 - 4))] + 5

Solution:

1. Solve the expression inside the round brackets: 6 - 4 = 2.
2. Then solve the outer round brackets: 9 - 2 = 7.
3. Divide 18 by the result inside the square brackets: 18 ÷ 7 ≈ 2.57.
4. Add 5 to the result: 2.57 + 5 = 7.57.

Answer: 7.57 (rounded to 2 decimal places)

BODMAS Questions for Class 6 with Curly Brackets

Question 1: Calculate: 4 + {6 × [2 + (3 - 1)]}

Solution:

1. Start with the expression inside the parentheses: 3 - 1 = 2.
2. Add 2 to 2 inside the square brackets: 2 + 2 = 4.
3. Multiply the result by 6 inside the curly brackets: 6 × 4 = 24.
4. Finally, add 4 to the result: 4 + 24 = 28.

Answer: 28

Question 2: Evaluate: {[(5 + 5) ÷ 2] × 3} - 4

Solution:

1. Solve the expression inside the parentheses: 5 + 5 = 10.
2. Divide by 2 inside the square brackets: 10 ÷ 2 = 5.
3. Multiply by 3 inside the curly brackets: 5 × 3 = 15.
4. Subtract 4 from the result: 15 - 4 = 11.

Answer: 11

Question 3: Simplify: 10 - {4 + [7 - (3 + 2)]}

Solution:

1. Start with the expression inside the parentheses: 3 + 2 = 5.
2. Subtract this result from 7 inside the square brackets: 7 - 5 = 2.
3. Add 4 to this result inside the curly brackets: 4 + 2 = 6.
4. Subtract the result from 10: 10 - 6 = 4.

Answer: 4